1 条题解
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0
#include <algorithm> #include <cstdio> #include <cstring> #include <vector> using namespace std; #define inf 0x3f3f3f3f #define mod 10000 typedef vector<int> vec; typedef vector<vec> mat; mat mul(mat &A, mat &B) { mat C(A.size(), vec(B[0].size())); for (int i = 0; i < A.size(); i++) { for (int k = 0; k < B.size(); k++) { for (int j = 0; j < B[0].size(); j++) { C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % mod; } } } return C; } mat pow(mat A, int n) { mat B(A.size(), vec(A.size())); for (int i = 0; i < A.size(); i++) B[i][i] = 1; while (n) { if (n & 1) B = mul(B, A); A = mul(A, A); n >>= 1; } return B; } int main() { int n; while (~scanf("%d", &n) && n != -1) { mat A(2, vec(2)); A[0][0] = 1, A[0][1] = 1; A[1][0] = 1, A[1][1] = 0; A = pow(A, n); printf("%d\n", A[0][1]); } return 0; }
- 1
信息
- ID
- 2071
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者